Calculus: Find the limits: x-√(x+6) /(√(4x+1) - 3) ; ∛(x)-2/(x-8) ; ∛(x+1)-1/x ; ∛(x-1)-1/√(2x)-2

Calculus: Find the limits: x-√(x+6) /(√(4x+1) - 3) ; ∛(x)-2/(x-8) ; ∛(x+1)-1/x ; ∛(x-1)-1/√(2x)-2

Here is the technique to solve this limits and how to find them in here.

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